Need help with this wordy GMAT question on student majors and fractions.?

Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students.
If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 3 times the fraction of first-year students who have declared a major,
What fraction of all the students in the dormitory are second-year students who have not declared a major?
A. 1/15
B. 1/5
C. 4/15
D. 1/3
E. 2/5
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Asked by M Rizwan 25 days ago

2 Answers
S Raghav

S Raghav

Seo Executive

This one's classic GMAT — lots of fractions but manageable if you break it into chunks.

• Total students = T
 • First-year = 0.5T → 4/5 haven’t declared major = 0.4T
 • So declared majors among first-years = 0.1T
 • Declared majors among second-years = 3 × 0.1T = 0.3T
 • Second-year total = 0.5T → not declared = 0.5T – 0.3T = 0.2T
 • So second-years with no major = 0.2T out of T total students = 0.2 = 1/5

Answer is B. All the values fall into place once you assign T and break the info into parts


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B.K Sharma

B.K Sharma

Detail-Oriented Financial Analyst

Looks messy at first, but it’s actually just a layered fractions problem. Start by assuming total students = T. Since half are first-years, both first-year and second-year totals = 0.5T.

Out of the first-years, 4/5 haven’t declared a major. So 0.5T × 4/5 = 0.4T haven’t declared, meaning 0.1T have declared.

Now, the declared majors among second-years is 3 times that → 3 × 0.1T = 0.3T.
 So among second-years:
 Declared = 0.3T
 Total = 0.5T
 So not declared = 0.5T – 0.3T = 0.2T

Now find the fraction of all students that are second-years with no major:
That’s 0.2T / T = 1/5

Final answer: B


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